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  • Common Error Messages · OCaml Documentation
    When the type of an object is not compatible with the context in which it is used, it is frequent to obtain this kind of message: "This expression has type X but is here used with type Y " means that if the contents of the expression is isolated (2 5), its type is inferred as X (float)
  • Ocaml _ Problème avec le type - CommentCaMarche
    Mon but était tout simple : créer une fonction qui affiche la valeur absolue de x entré dans le code source Ainsi ce code fonctionne : Mais dès que je rajoute une valeur négative il y a
  • This expression has type int but an expression was expected of . . . - OCaml
    Hey guys, I can’t find the answer to this error This expression has type int but an expression was expected of type Z t, it’s giving the error with this match num with | 0 -> Z of_int(1) | 1 -> Z of_int(2) | _ -> Z of_int(3 * (s1 (num-1)) + (sum_s1 num)) How am I supposed to fix this error? Any tips are always helpful! Thanks!!
  • [OCaml] Error: This expression has type. . - Caml - Developpez. com
    Error: This expression has type int -> 'a array ==> il trouve que tu es en train de rendre une fonction, de type int -> 'a array Or tu tentes de retourner inverse_rec (i-1), soit la fonction inverse_rec déjà appliqué à un entier
  • This expression has type lt;x gt; but an expression was expected of type . . .
    The problem here is simply that there's a missing else branch Even if the expression is logically consistent and total, OCaml don't care According to the compiler, this is a simple matter of types, and you, sir, you have the wrong type!
  • Problème! Erreur de compilation Caml. - Caml - Developpez. com
    Le compilateur te dit que tu mets un entier (int) à un endroit où une action (type unit) est attendue File "D: cours M1 AC Algo et Complexite Projet arithmetique ml", line 15, characters 2-4: Error: This expression has type int but an expression was expected of type
  • Problem with has type X but expected type unit - OCaml
    The issue is in your definition of print_kind : f x, y , z, w is parsed as (f x), y , z , w Also rather than matching on your tuple argument with let f tuple = match tuple with x,y,z,w -> … , you can write directly let f (x,y,z,w) = …





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