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  • Is a `=default` move constructor equivalent to a member-wise move . . .
    [ Note: The copy move constructor is implicitly defined even if the implementation elided its odr-use (3 2, 12 2) —end note ][ ] and paragraph 15 which says: The implicitly-defined copy move constructor for a non-union class X performs a memberwise copy move of its bases and members [ Note: brace-or-equal-initializers of non-static data
  • What is std::move (), and when should it be used? - Stack Overflow
    -1 "std::move() is the C++11 way to use move semantics" Please fix that std::move() is not the way to use move semantics, move semantics are performed transparently to the programmer move its only a cast to pass a value from one point to another where the original lvalue will no longer be used –
  • c++ - What is move semantics? - Stack Overflow
    The move constructor will transfer ownership from the temporary to c Again, this is exactly what we wanted The move constructor transfers ownership of a managed resource into the current object Move assignment operators The last missing piece is the move assignment operator
  • c++ - Difference between the move assignment operator and move . . .
    A move constructor is executed only when you construct an object A move assignment operator is executed on a previously constructed object It is exactly the same scenario as in the copy case Foo foo = std::move(bar); construction, invokes move constructor foo = std::move(other); assignment, invokes move assignment operator
  • c++ - Default move constructor assignment and deleted copy constructor . . .
    user-declared means either user-provided (defined by the user), explicitly defaulted (= default) or explicitly deleted (= delete) in contrast with implicitly defaulted deleted (such as your move constructor) So in your case, yes the move constructor is implicitly deleted because the copy-constructor is explicitly deleted (and thus user
  • Why is there no default move-assignment move-constructor in early . . .
    The implicit generation of move constructors and assignment operators has been contentious and there have been major revisions in recent drafts of the C++ Standard, so currently available compilers will likely behave differently with respect to implicit generation
  • Is there a point to define move-only objects in c++11?
    I had a question about using unique-ptrs before I get this answer recommending to use move-only objects I defined a class as below: class B { const string objName; public: B ( B amp; a
  • When to use Move Constructors Assignments - Stack Overflow
    In cases where copy is OK but move preferred a compiler will hopefully chose to move when it can (i e test with vector push_back which will with some compilers move or emplace_back if it's reasonable, buying instant performance gains), therefore even in copy constructor objects a defined move constructor may automatically be selected improving
  • c++ - How to define a move constructor? - Stack Overflow
    The move constructor is correct 1 but the rest of the class isn’t, you are violating the rule of three: your class needs an appropriate copy constructor and copy assignment operator Is there a better way to implement the move constructor? A better way to write the move constructor looks as follows:
  • Is it necessary to implement move constructor for a class without . . .
    No, your class does not need a move-ctor or move-assignment-operator You can't move static arrays, you can only copy their content So a potential move-ctor would do the same as the copy-ctor The same goes for assignment operators





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