英文字典中文字典


英文字典中文字典51ZiDian.com



中文字典辞典   英文字典 a   b   c   d   e   f   g   h   i   j   k   l   m   n   o   p   q   r   s   t   u   v   w   x   y   z       







请输入英文单字，中文词皆可：


请选择你想看的字典辞典：
单词字典翻译
1000查看　1000　在百度字典中的解释百度英翻中〔查看〕
1000查看　1000　在Google字典中的解释Google英翻中〔查看〕
1000查看　1000　在Yahoo字典中的解释Yahoo英翻中〔查看〕

安装中文字典英文字典查询工具!


中文字典英文字典工具:
选择颜色:
输入中英文单字

































































英文字典中文字典相关资料:


  • How much zeros has the number $1000!$ at the end?
    yes it depends on $2$ and $5$ Note that there are plenty of even numbers Also note that $25\times 4 = 100$ which gives two zeros Also note that there $125\times 8 = 1000$ gives three zeroes and $5^4 \times 2^4 = 10^4$ Each power of $5$ add one extra zero So, count the multiple of $5$ and it's power less than $1000$
  • What does it mean when something says (in thousands)
    I'm doing a research report, and I need to determine a companies assets So I found their annual report online, and for the assets, it says (in thousands) One of the rows is: Net sales $ 26,234
  • How to calculate 1 in _______ chance from a percentage?
    I am wondering, how do I ago about calculating 1 in chances from a percentage? Example: A 1 in 2 chance is 50% and 0 5 as a decimal What I want to do: I have the value 0 1431 (14 3%) and want to
  • probability - 1 1000 chance of a reaction. If you do the action 1000 . . .
    So for your example, it would be 1-((1–1 1000)^1000) which equals 1-(0 999^1000), which turns out to be about 0 63230457, or 63 230457% There is a lot of confusion about this topic, as intuitively, you would think that if the odds are 1 1000 playing 1000 times would guarantee a win
  • Is there a shortcut for raising 2 to the power of a number (e. g.
    Simple way to mentally estimate 2 to any power: $2^{10} \approx 1,000$ (actually 1,024) E g , $2^{27} = 2^{20} \times 2^7 \approx 1,000^2 \times 128 = 128’000,000$ Real answer is 134 million - not bad for a mental estimate You’ll always be a bit low because you estimate 1,024 as 1,000, but you’ll be close The higher the power, the
  • Find the sum of all the multiples of 3 or 5 below 1000
    First of all, stop thinking on the number $1000$ and turn your attention to the number $990$ instead If you solve the problem for $990$ you just have to add $993, 995, 996$ $999$ to it for the final answer This sum is $(a)=3983$ Count all the #s divisible by $3$: From $3$ to $990$ there are $330$ terms
  • Expected value of a coin toss - Mathematics Stack Exchange
    You flip a coin If you get heads you win \\$2 if you get tails you lose \\$1 What is the expected value if you flip the coin 1000 times? I know that the expected value of flipping the coin once i
  • How to calculate a Modulo? - Mathematics Stack Exchange
    I really can't get my head around this "modulo" thing Can someone show me a general step-by-step procedure on how I would be able to find out the 5 modulo 10, or 10 modulo 5
  • How do you calculate the modulo of a high-raised number?
    I need some help with this problem: $$439^{233} \\mod 713$$ I can't calculate $439^{223}$ since it's a very big number, there must be a way to do this Thanks
  • Calculate logarithms by hand - Mathematics Stack Exchange
    I'm thinking of making a table of logarithms ranging from 100-999 with 5 significant digits By pen and paper that is I'm doing this old school What first came to mind was to use $\\log(ab) = \\lo





中文字典-英文字典  2005-2009